the perineter of triangle ABC is 50 cm. its sides AB, BC and AC are respectively 15 cm, 10 cm and (x+4) cm. find the value of x ?
Answers
Answered by
6
15+10+x+4=50
29+x=50
x=50-29
x=21 answer
29+x=50
x=50-29
x=21 answer
kritiku2005:
Please mark it the brainliest answer
Answered by
10
we have
perimeter∆abc=50cm
AB=15cm
BC=10CM
AC=(X+4)CM
WE know
perimeter=AB+BC+AC
50=15+10+X+4
50=29+X
X=50-29
X=21 ans.
perimeter∆abc=50cm
AB=15cm
BC=10CM
AC=(X+4)CM
WE know
perimeter=AB+BC+AC
50=15+10+X+4
50=29+X
X=50-29
X=21 ans.
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