Question

the period of 1.34 bar​

Answer 1

ANSWER

In 1.34bar  

let the 1.34 bar = x

as there are numbers under the bar,then multiply by 100 on both sides

then  

100x =134.34bar

subtract x from both sides,

99x=133

x= 133/99

 IN 4.12 bar,

let 4.12 bar =y

as there are 2 numbers under bar then multiply by 100 on both sides

then

412.12 bar = 100y

subtract y from both sides,

408 = 99y

y  = 408/99  

then  

133/99 + 408/99

(133+408)/99

541/99

MARK AS BRAI9NLIEST IF ITS HELPFUL TO YOU