Physics, asked by MujawarAliya, 1 month ago

The period of a conical pendulum in terms of its length (l) semivertical angle (Ө) and acceleration due to gravity (g) is

1/2π √((l cos⁡Ө)/g)

1/2π √((l sin⁡Ө)/g)

4π√((l cos⁡Ө)/4g)

4π√((l tan⁡Ө)/g)​

Answers

Answered by mishrapriya18
2

Answer:

1/2π √((l sin⁡Ө)/g)

Explanation:

The period of a conical pendulum in terms of its length (l) semivertical angle (Ө) and acceleration due to gravity (g) is

:. 1/2π √((l sin⁡Ө)/g)

Answered by SteffiPaul
1

The period of a conical pendulum in terms of its length (l), semi vertical angle (θ) and acceleration due to gravity (g) is 4π√((lcosθ)/4g).

Correct Answer is the option (3).

Explanation:

A conical pendulum consists of a bob of mass 'm' revolving in a horizontal circle with a uniform speed 'v' at the end of the string of the length 'l'.

The string makes a constant angle 'θ' with the vertical.

The period of a conical pendulum, T = 4π√((lcosθ)/4g),

where T is the time period, l is the length of the string, θ is the vertical angle and g is the due to acceleration gravity.

When θ = 0°, then the period of conical pendulum becomes

T =2\pi \sqrt{\frac{l}{g} }

where T is the time period, l is the length of the string and g is the due to acceleration gravity.

#SPJ2

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