Question

The period of a planet around sun is 27 that if earth. The raito of radius of planet orbit the radius of earth orbit is

Answer 1

Answer:

9 (nine)

Explanation:

\\Let p=planet and e=earth. Given Tp/Te = 27.

As we all know T^2 = kR^3, this implies

Tp/Te = (Rp/Re)^3/2

or Rp/Re = (Tp/Te)^2/3

               = (27)^2/3

               = 9    (Soln.)

Answer 2

Answer:

The eccentricity of an elliptical orbit can also be used to obtain the ratio of the periapsis to the apoapsis:

ra / rp = 1-e / 1+e

ra - radius at apoapsis (i.e., the farthest distance of the orbit to the center of mass of the system)

rp - radius at periapsis (the closest distance)

e - eccentricity vector.

A number of near-integer-ratio relationships between the orbital frequencies of Jupiter and Earth are 1:12. Mismatch after one cycle of planets is 49.1°. Randomization time is 40 years. Probability is 0.28.