Question

The period of a satellite in a circular orbit of radius r is t. The period of another satellite in circular orbit of radius 4r is

Answer 1

Answer:

Time period of the another satellite will be 8 times greater than the period of first satellite

Explanation:

By Law Of Time Period Of Satellites,{T1 /T2}^2={R1/R2}^3

Here R2=4R1

so, {T1/T2}^2={R1/4R1}^3

     {T1/T2}^2={1/4}^3

     {T1/T2}^2=1/64

     T1/T2=1/8

     T2=8T1