Question

The period of a simple pendulum is given byT=2pi √l÷g.Write what is the percentage error in g.If the percentage error in length(l) is 2% and percentage error T is 5%.

Answer 1

Answer: 8%

Explanation:

(∆T / T)^2 = ∆l/l +∆g/g

2.∆T/T = ∆l/l + ∆g/g

2×5 = 2 + ∆g/g

So percentage error = 8%