The period of cos CM0/2 ) is
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Answer:
A function is periodic if f(x)=f(x+T).
Let us assume that cos(x
2
) has a period of T. In that case:
cos(x+T)
2
=cosx
2
⇒(x+T)
2
=2nπ+x
2
⇒x
2
+T
2
+2xT=2nπ+x
2
⇒T
2
+2xT−2nπ=0
As we can see, T is dependent on the value of x and hence, is not a constant.
So cos(x
2
) is not periodic.
So, we can say that period of cos(x
2
) does not exist
I think so it is correct
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