Question

the period of cos (theta/2) is
​

Answer 1

Step-by-step explanation:

the period of cos (theta/2) is 4 pie.

Answer 2

SOLUTION

TO DETERMINE

$\displaystyle \sf{The \: period \: of \: \: \cos \frac{ \theta}{2} }$

FORMULA TO BE IMPLEMENTED

For a function f(x) of the form f(x) = a cos(bx+c)

Amplitude = | a |

$\displaystyle \sf{The \: period \: = \: \frac{2\pi}{b} }$

EVALUATION

Here the given function is

$\displaystyle \sf{f( \theta) = \: \: \cos \frac{ \theta}{2} }$

Hence

$\displaystyle \sf{The \: period \: of \: \: \cos \frac{ \theta}{2} }$

$\displaystyle \sf{ = \frac{2\pi}{ \frac{1}{2} } }$

$\displaystyle \sf{ = 4\pi }$

FINAL ANSWER

$\displaystyle \sf{The \: period \: of \: \: \cos \frac{ \theta}{2} = 4\pi }$

━━━━━━━━━━━━━━━━

LEARN MORE FROM BRAINLY

Prove that the curl of the gradient of

(scalar function) is zero

https://brainly.in/question/19412715