Question

The Period of f(x)=tan(ax+b)= is​

Answer 1

The Period of f(x) = tan(ax+b) is π/a

Step-by-step explanation:

Given

$f(x)=\tan (ax+b)$

To find out

Period of f(x)

Solution:

Period of any function is the value after which the function repeats

Let the time period is T

$\tan [a(x+T)+b]=\tan (ax+b)$

$\implies \tan (ax+aT+b)=\tan (ax+b)$

$\implies \tan (ax+b+aT)=\tan (ax+b)$

We know that minimum value for which $\tan x$ repeats itself is is $\pi$

Thus,

$aT=\pi$

$\implies T=\frac{\pi}{a}$

Hope this answer is helpful.

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