Question

The period of oscillation of a particle in SHM is 4s and its amplitude of vibration is 4cm. The distance of the particle 1/3 s after passing the mean position is
1)1.33cm 2)2cm 3)3cm 4)2.33cm

Answer 1

2. 2cm I hope it will right

Answer 2

y = asinwt

=asin(2π/T)*t

=4sin(2π/4)*1/3

=4sin(π/6)

=4*1/2

=2

Hence the answer is 2cm.

Hope it helps.