Question

the period of oscillation of a pendulam t=2π(2÷g measured value of l is 20.0cm known to 1mm accuracy and time of 100ossicaltion of the pendulam is formed to be 90sec. using a wrist cause of 1sec. revolution what is the accuracy in the determination of g.
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Answer 1

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Answer 2

Hi I am Swarup I am here to help you with this question

Explanation

T=Time period of one oscillation

t= Time period of 100 oscillation

For 100 oscillation,t= 100T

∆g/g = ±( ∆L/L +2 ∆T/T)

∆g/g = ±(0.1/20+2/90) = ±2.7%

Hence, error in gravity is ±2.7%