Question

the period of oscillation of a simple pendulum of constant length. at earth surface is T. Its period inside mine is?​

Answer 1

Time per of simple pendulum is

T = 2pi*root(l/g)

Hope it helps you

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Answer 2

Answer:

Greater than T

Explanation:

Wkt,

T=2π√(L/g)

Earth's gravity decreases as we go down a mine..

And by above eq. T is inversely proportional to G ! It means as G decreases T increases..

So Time period is Greater than T