Question

The period of revolution of a particle along a circular path of radius 10m is 40s .The displacement of the particle after two and half minutes from its starting point is

options
10m
14.14m
0
28.28 m

Answer 1

the displacement is 14.14m

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Answer 2

Answer:

The displacement of the particle is 14.14m.

Step-by-step explanation:

The word displacement means that an object contains moved, or includes been displaced. Displacement exists determined to be the difference in the position of an object.

Given:

The period of revolution of a particle along a circular path of radius 10m is the 40s.

To find:

The displacement of the particle after two and half minutes from its starting point.

Step 1

1 round - 40 sec

time = 2.5 mm

= 100 s

Number of rounds in

$\begin{aligned} 1605 &=\frac{150}{40} \\ &=375 \text { rounds } \end{aligned}$

Step 2

Displacement $&=\sqrt{10^{2}+10^{2}}$

$&=\sqrt{100+100}$

Simplifying the above equation, we get

$&=\sqrt{200}$

$&=\sqrt{2 \times 100}$

$&=10 \sqrt{2}$

= 14.14 m

Therefore, the displacement of the particle is 14.14m.

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