The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the is how many times greater than that of B from the sun
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Answer:
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Explanation:
ANSWER
Time period T
2
=
GM
4π
2
R
3
i.e T
2
∝R
3
⇒(
T
2
T
1
)
2
=(
R
2
R
1
)
3
⇒8
2
=(
R
2
R
1
)
3
⇒
R
2
R
1
=8
2/3
=4
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