The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the is how many times greater than that of B from the sun
Answers
Answered by
77
Time period of planet B = T
radius of planet A = a
radius of planet B = b
time period o A = 8T
by Kepler's 3rd law
T/8T = (b)³/ (a)³
(b/a)³= 1/8
taking the cube root we get
b/a = 1/2
or
a = 2b
radius of planet A = a
radius of planet B = b
time period o A = 8T
by Kepler's 3rd law
T/8T = (b)³/ (a)³
(b/a)³= 1/8
taking the cube root we get
b/a = 1/2
or
a = 2b
Answered by
31
T/8T = (b)³/ (a)³
(b/a)³= 1/8
taking the cube root we get
b/a = 1/2
or
a = 2b
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