Physics, asked by kiean1107, 6 months ago

The period of revolution of the moon around the earth is 27.3 days. Remember
that this is the period with respect to the fixed stars (the period of revolution
with respect to the moving earth is about 29.5 days; it is this period that is
used to fix the duration of a month in some calendars). The radius of moon’s
orbit is 3.84 × 10^8
m (60 times the earth’s radius). Calculate the centripetal
acceleration of the moon and show that it is very close to the value given by
9.8 ms–2 divided by 3600, to take account of the variation of the gravity as 1/
r2

Answers

Answered by kirti112327
0

Answer:

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