The period of shm of a particle is 12 second . The phase difference between the positions at t=3second and=4second will be?
Answers
Answered by
3
w = 2 * pi * f = 2 * pi / T where w is the angular frequency
w = pi / 6
w t2 - w t1 = w (t2 - t1 ) = w = pi / 6 = 30 deg the phase difference
Similar questions