Question

the period of SHM of a particle with maximum velocity 50 cm/s and maximum acceleration 10 cm / {s}2

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Answer 1

V max=Aw

A max =Aw^2

now,

V max = Aw = 1 = 50 = 5

A max Aw^2 w 10

now 1 =5

w

so w = 1

5

w= 2 π

T

now

1 = 2 π

5 T

T=10 π (π=3.14)

T = 3.14×10

T= 31.4 seconds