the period of SHM of a particle with maximum velocity 50 cm per second and the maximum acceleration 10 centimetre per second square is
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1
Answer:
31.42 sec
Explanation:
ANSWER
V
max
=Aw=50m/s
a
mas
=Aw
2
=10cm/s
2
w
1
=5
w=
5
1
=
T
2π
T=10π
=31.42sec
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