Question

The period of simple pendulum inside a stationary lift is t.If the lift accelerates downwards with an acceleration g/4 the period of the pendulum will be

Answer 1

Answer:

Given:

Time period of a simple pendulum inside a stationary lift = T

Lift starts accelerating downwards with (g/4) m/s².

To find:

New time period of the pendulum.

Concept:

First of all, you need to know the concept of pseudo- force. When a body is in an non-inertial reference frame, it experiences pseudo- force.

The direction of the pseudo- force is opposite to the direction of the applied force.

Calculation:

We know that ,

T = 2π √(l/g) ............( Time period in stationary conditions)

Now in the accelerating lift ( g/4 m/s² downwards),

the lift will experience a pseudo-force upwards.

So net acceleration experienced by the pendulum

= g - g/4

= ¾g m/s².

So new time period

= T"

= 2π√{l/(¾g)}

=√3/2 × 2π√(l/g)

= √3T/2 .............[ as 2π√(l/g) = T ]

So final answer = √3T/2.

Answer 2

Answer:

Explanation:

Refer the below attachment.