The period of sin'3 x + cos'3 x is
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Answer:
cos3x + sin3x = (1/2)(cos x + sin x)(2 - sin 2x)
= (1/2)(cos x + sin x)(2 - 2sin x cos x)
= (cosx + sin x)(1 - sin x cos x)
= cos x + sin x - sin x cos2x - sin2x cos x
= cos x - sin2x cosx + sin x - sin x cos2x
= cos x(1 - sin2x) + sin x(1 - cos2x)
= cos x (cos2x) + sin x (sin2x)
= cos3x + sin3x
Step-by-step explanation:
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The peroid is 1 becuase if sin is max then cos is minimum
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