Question

The period of sin^3 x + cos^3 x is​

Answer 1

Answer:

] To find period of

f(x)=sin3xcos[3x]−cos3xsin[3x]

As

sin(A−B)=sinAcosB−cosAsinB

so, sin3xcos[3x]−cos3xsin[3x]

=sin(3x−[3x])

As x−[x]={x}

so, sin(3x−[3x])

=sin({3x})

the period of fractional part of x is 0 to 1

so, period of

b(x)=sin{3x}

is

3

1

Answer 2

It's correct answer is

2π