Question

The period of sin² θ is(a) π²(b) π(c) 2π(d) π/2

Answer 1

Answer:

The correct answer is option (b)

Step-by-step explanation:

Concept : If period of $f(x)$ is T, then period of $a+bf(dx+e)$ is $\frac{\text{T}}{|d|}$

Now

We know that  $\sin^2\theta=\frac{1-\cos 2\theta}{2}=\frac{1}{2}-\frac{1}{2}\cos(2\theta)$

Thus the period is $\frac{2\pi}{2}=\pi$