The period of the function f (x)
cosec^2 3x + cot 4x is
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Step-by-step explanation:
Now, cosec^2 3x has a period of pi/3(60 deg). f(x) has a period of l.c.m (pi/3,pi/4)= l.c.m(pi,pi)/ h.c.f(3,4). Therefore, period of the function is f(x)= cosec^2 3x+cot 4x is pi .
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Answered by
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Given : function f(x) = cosec² 3x + cot 4x
To Find : Period
Solution:
Period of a function is the interval at which function returning to the same value.
if p is the period of a function f(x)
=> f(x + p) = f(x)
f(x) = cosec² 3x + cot 4x
Period of cosec²x = π
Period of cosec²3x = π/3
Period of cotx = π
Period of cot4x = π/4
LCM ( π/3 , π/4 )
LCM of numerators/HCF of denominators
= π / 1
= π
Hence period of f(x) = cosec² 3x + cot 4x is π
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