the periodic time of a body executing simple harmonic motion is 2s. after how much time interval from t=0 will its displacement be half the amplitude
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Answer:
Given,
T=4sec
Displacement equation is S.H.M is given by
y=asinωt. . . . . .(1)
If y=
2
a
Equation (1) becomes,
2
a
=asinωt
sinωt=0.5
ωt=sin
−1
(0.5)=
6
π
T
2π
t=
6
π
t=
12
T
t=
12
4
t=
3
1
sec
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