Physics, asked by nchijioke69, 3 days ago

The permittivity of diamond is 1.46×10^-10C^2N^-1m^2 what is the dielectric constant of diamond?
What is it's susceptibility?

Answers

Answered by deepuchauhan628
0

Answer:

diamond is very hard substance in the world

Answered by dualadmire
0

Thus, the dielectric constant ( k ) of diamond is 16.50

and the susceptibility ( χ )  of diamond is 15.50

Given: The permittivity of diamond is 1.46×10^-10 C^2.N^-1.m^2

To Find:

The dielectric constant of diamond and its susceptibility

Solution:

  • We know that the dielectric constant of a  substance can be found by calculating the ratio between the permittivity of the substance and the permittivity of free space.

Here, the permittivity of the diamond = 1.46 × 10^-10 C^2.N^-1.m^2

and permittivity of free space = 8.85 × 10^-12 C^2.N^-1.m^2

The dielectric constant ( k ) = (1.46 × 10^-10) ÷ (8.85 × 10^-12)

                                                = 16.50

 Now susceptibility ( χ ) can be found using the formula;

 Dielectric constant ( k ) = 1 + susceptibility ( χ )

∴ susceptibility ( χ ) = 16.50 - 1

                                  = 15.50

Thus, the dielectric constant ( k ) of diamond is 16.50

 and the susceptibility ( χ )  of diamond is 15.50

#SPJ2

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