Question

The permittivity of medium in 26.55 *10 power of -12 C power of 2 Nm square .The dielectric constant medium will be

Answer 1

dielectric constant of medium is 3

we have to find out dielectric constant of medium when permittivity of medium is given. and i.e., $\epsilon_r$ = 26.55 × 10^-12 C²/Nm²

dielectric constant is the ratio of primitive of medium to permittivity of vaccum (free space)

experimentally, permittivity of vaccum is $\epsilon_0$ = 8.85 × 10^-12 C²/Nm²

so, K = 26.55 × 10^-12/(8.85 × 10^-12)

= 3

hence, dielectric constant of medium is 3

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Answer 2

Explanation:

Permittivity of the medium is 26.55x10 C²/Nm²

Dielectric constant is the ratio of permittivity of medium to permittivity of vaccum (free space).

Experimentally, permittivity of vaccum is 8.85 × 10^-12 C²/Nm².

So dielectric constant is 26.55x10/(8.85x10^-12)

= 3x10^13