Math, asked by HiteshJoshi7, 3 months ago

The perpendicular AD on the base BC of a triangle ABC intersects BC at D so that DB = 3CD.
Prove that 2AB² = 2AC²+ BC²

Answers

Answered by qwerf56

1

Answer:

answer are getting below:-

Attachments:

Answered by sambhav0355

2

Step-by-step explanation:

2AB²= 2AC²+BC²

BC²=(2)²-(2)²

=4-4

=0

So,BC²=0

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