Question

the perpendicular distance between the pair of opposite sides of a parallelogram are 3 cm and 4 cm and one of its angle measures 60 degree using ruler and compass only construct the parallelogram​

Answer 1

Answer:

1. draw two parallel lines  L 1 and L 2 which have distance between 3 cm and 2. let point A on line L 23. make 60 degree angle at point A and we get point D on L 14. draw a arc of  radius of of 4 cm 5. let point C and make 60 degree angle at point C which is touch the arc at point F then parallelogram ABCD is constructed    

Answer 2

$ABCD$ is the required parallelogram.

Step-by-step explanation:

Given,

Construct a parallelogram where perpendicular distance between the pair of opposite sides are $3\ cm$ and $4\ cm$

Following steps:

• Draw two parallel line $L_{1}\ and\ L_{2}$ with distance $3\ cm$

• $A$ any point on line $L_{2}$ draw an angle $60\ degree$ by using protector where angle line meet at $D$ on line $L_{1}$
• At point $D$, draw an angle $90\ degree$ with $AD$ as one sides like $\angle ADX=90\ degree$
• Cuts a point $E$ on line $DX$ like $DE=4\ cm$

• Through point $E$, draw a parallel line with $AD$ which meet line $L_{1}\ and\ L_{2}$ at $B$ and $C$

Now, $ABCD$ is the required parallelogram.