the perpendicular distance between two parallel lines 3x+4y-6=0 and 6x+8y+7=0 is equal to
Answers
Answered by
0
Step-by-step explanation:
d=c2-c1/√(a^2+b^2)
d=(6-7/2)/5
d=5/2/5
d=1/2
Answered by
0
Answer:
what is your ping id please give me
Similar questions