Question

The perpendicular distance of a point P (5, 8) from the y-axis is:

1 point

5

8

3

13

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Answer 1

Answer:

5

Step-by-step explanation:

When a perpendicular is drawn from (5, 8) on y-axis, it intersects the y-axis at 8. So that point becomes (0, 8).

 Using distance formula,

⇒ √(5 - 0)^2 + (8 - 8)^2

⇒ √5^2 + 0^2

⇒ √5^2

⇒ 5

Answer 2

Hey there!

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Answer:

★ The perpendicular distance of a point P (5, 8) from the y-axis is [We can find the distance between these points by using formula].

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Using distance formula:-

★ $\sf{Distance = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}}$

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Calculations:-

$\sf{\longrightarrow Distance = \sqrt{(x_{5} - x_{0})^{2} + (y_{8} - y_{8})^{2}}}$

$\sf{\longrightarrow Distance = \sqrt{(5 - 0)^{2} + (8 - 8)^{2}}}$

$\sf{\longrightarrow Distance = \sqrt{5^{2} + 0^{2}}}$

$\sf{\longrightarrow Distance = \sqrt{5^{2} + 0}}$

$\sf{\longrightarrow Distance = \sqrt{5^{2}}}$

${\longrightarrow{\boxed{\bold{Distance = 5}}}}$

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Therefore, 5 units is the required distance between them.

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Thanks!