Question

The perpendicular distance of point A (6,9) from the x-axis and y- axis
is
1) 6 units, Sunits
B) 9 units , 6units
C) 6 units , 15 units
D) 15 units, Sunits​

Answer 1

B is the correct option.

Answer 2

Given,

The coordinates of the point A = (6,9)

To find,

The distance between the point with X axis and Y axis.

Solution,

We can simply solve this mathematical problem by using the following mathematical process.

Here, the following method will require no mathematical calculation.

In the given point A,

Abscissa (x coordinate) = 6

Ordinate (y coordinate) = 9

Now, abscissa or x coordinate is always the perpendicular distance from the Y axis and the ordinate or y coordinate is always the perpendicular distance from X axis.

From the above mentioned principle,

Distance from the Y axis = 6 Units

Distance from X axis = 9 units

[Remembering trick : x coordinate for Y axis and y coordinate tor X axis.]

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And, this method will require mathematical calculation.

From the given point A if we draw two perpendicular straight lines on X axis and Y axis then those two straight line will intersect X axis and Y axis at the points (6,0) and (0,9) respectively.

[ Pattern : If the point is (x,y) ; then intersection point on X axis is (x,0) and intersection point on Y axis is (0,y)]

Now, if we calculate the distance between the given point A and each of the previously obtained intersection points, then we will get the distance between the given point and X axis, Y axis.

Distance from X axis = Distance between the point A and intersection point on X axis = √(6²-6²)+(9²-0²) = √(0+81) = 9 units

Distance from Y axis = Distance between the point A and intersection point on Y axis = √(9²-9²)+(6²-0) = √(0+36) = 6 units

Hence, the distance from X axis and Y axis are 9 units and 6 units respectively. (Option B)