Question

the perpendicular distance of the point (6,8) from the origin is? (long answer) *2 points​

Answer 1

Answer:

The perpendicular distance of (x, y) from origin is

$\sqrt{ {x}^{2} + {y}^{2} }$

The perpendicular distance of (6,8)=

$= \sqrt{ {6}^{2} + {8}^{2} }$

$= \sqrt{36 + 64}$

$= \sqrt{100}$

$= 10$

Answer 2

The distance of the point P(−6,8) from the origin is 62+82=36+64=100=10 units.