Question

the perpendicular distance of the point A(-3, 7) from y axis is​

Answer 1

Answer:

a Will we 3

Step-by-step explanation:

I think it's help you

Answer 2

The perpendicular distance of the point A (- 3, 7) from the y-axis is 3 units.

Tips:

The perpendicular distance of the point A $(x_{1},y_{1})$ from the straight line ax + by + c = 0 is

d = $\dfrac{|ax_{1}+by_{1}+c|}{\sqrt{a^{2}+b^{2}}}$

Step-by-step explanation:

We know that, the equation of the y-axis is x = 0, and we can write it as 1x + 0y + 0 = 0.

So, the required perpendicular distance of the point A (- 3, 7) from y-axis is

d = $\dfrac{|1(-3)+0(7)+0|}{\sqrt{1^{2}+0^{2}}}$ units

= $\dfrac{|-3|}{1}$ units

= 3 units

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