Question

The perpendicular distance of the point p (-2,7) from x-axis.

Answer 1

Answer:

The required distance is 7 units.

Solution:

The given point is P (- 2, 7)

We have to find the distance of the point P from the x-axis.

The equation of x is y = 0

Then the distance of P from y = 0 is

= | (- 2).0 + 7.1 | / √(0² + 1²) units

= 7 units

Formula:

If (p, q) be any given point and ax + by + c = 0 be any line given, then the distance of (p, q) from the line is given by

= | ap + bq + c | / √(a² + b²) units

Answer 2

Answer:

The distance of .A (-2,7) from x-axis is 7 units

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