Question

The perpendicular distance of the point P(-2,7)from x-axis is 2 units

Answer 1

Answer:

No

Step-by-step explanation:

Given that

Point P ( - 2 ,7)

Here x is negative and y is positive that is why this point is in second quadrant.

From that graph

Point O ( -2 ,0)

We know that distance between to point given as

$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)}$

$d=\sqrt{(-2+2)^2+(0-7)}$

d = 7

d is the perpendicular distance of point P from x axis.