Question

The perpendicular distance of the point P (- 3,8 )from x axis

Answer 1

Given: The point P(-3 , 8)

To find: The perpendicular distance of the point P (- 3,8 ) from x axis.

Solution:

• Now we have given the point as P(-3 , 8).

• The point is given by perpendicular on x axis, so point will be Q(-3,0).

• So the distance between P and Q will be:

                 PQ = √ { (x2-x1)² + (y2-y1)² }

                 PQ = √ { (-3-(-3))² + (0-8)² }

                 PQ = √ { 0 + 64 }

                 PQ = √64

                 PQ = 8 units.

Answer:

              So the distance between the perpendicular distance of the point P (- 3,8  ) from x axis is 8 units.

Answer 2

Answer:

Always remember in these kinds of questions, when they ask the perpendicular distance from x axis, it will be the value of the no. lying in the ordinate, i.e, the y-axis.

If they ask the perpendicular distance from the y-axis, the perpendicular distance will be the value of the no. lying in the abcissa, i.e. the x-axis.

So here, when they have asked for the perpendicular distance from x axis,

(x,y)=(-3,8)

Hence the perpendicular distance is the y value, i.e 8 units.

Hope you find it helpful.

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Step-by-step explanation: