Question

The perpendicular distance of the point Q(-8,-7) from x-axis is
(a) -8 (b) 8 (c) -7 (d) 7​

Answer 1

Given:-

• Q(-8,-7)

To Find:-

• The perpendicular distance of the point Q(-8,-7) from x-axis

Solution:-

Q=(-8,-7)

Perpendicular distance means the x-coordinate on the x-axis will also be (-8). On x-axis, the y-coordinate is always = 0.

∴ second point, say, P = (-8,0).

Distance between two points $Q(x _ 1,y _1)$ and $P(x_ 2, y_ 2)$ is given by:

$D = \sqrt{ {( x _2 - x _1 )}^{2} + {(y_ 2 - y _1)}^{2} }$

Points= Q=(-8,-7) and P = (-8,0).

So,

$D = \sqrt{ {( - 8 - ( - 8))}^{2} + {(0 - ( - 7))}^{2} }$

$= > D = \sqrt{(0) + {7}^{2} }$

$= > D =±7$

As Distance is Scalar, It Can't be Negative.

$\therefore \: D = + 7 \: units$

Option d) 7 is the correct Answer

Answer 2

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