Question

the perpendicular distance of the straight line 3x+4y+m=0 from the origin is 2,find m​

Answer 1

$\huge{\underline{\underline{\purple{♡Solution→}}}}$

Given →

$3x + 4y = 0$

• $d = 2$

Comparing the equation by ax + by + c = 0

→

a = 3 , b = 4, c = m , x1 = 0 , y1 = 0

we know that →

$d = \frac{a \times x1 + b \times y1 + c}{ \sqrt{ {a}^{2} + {b}^{2} } }$

$2 = \frac{3 \times 0 + 4 \times 0 + m}{ \sqrt{ {3}^{2} + {4}^{2} } }$

$2 = \frac{m}{ \sqrt{9 + 16} }$

$2 = \frac{m}{ \sqrt{25} } \\ 2 = \frac{m}{5}$

$</strong><strong>\</strong><strong>b</strong><strong>o</strong><strong>x</strong><strong>e</strong><strong>d</strong><strong>{</strong><strong>m</strong><strong> = </strong><strong>±</strong><strong>10</strong><strong>}</strong><strong>$

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