Question

The perpendicular drawn from the centre of a circle to a chord , other than a diameter bisesects the chord. (show the diagram​)

Answer 1

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Answer ⤵️

To prove that the perpendicular from the centre to a chord bisect the chord.

Consider a circle with centre at O and AB is a chord such that OX perpendicular to AB

To prove that AX=BX

In ΔOAX and ΔOBX

∠OXA=∠OXB [both are 90 ]

OA=OB (Both are radius of circle )

OX=OX (common side )

ΔOAX≅ΔOBX

AX=BX (by property of congruent triangles )

hence proved.

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