Question

the perpendicular drawn on a straight is?​

Answer 1

Answer:

Let y=mx+c line

distance from (0,0) to y=mx+c is p

p=∣∣∣∣∣​1+m2

​c​∣∣∣∣∣​

For x intercept y=0

Therefore x intercept : x=m−c​

For y intercept x=0

y intercept: y=c

M is a mid-point of intercept made by line y−mx−c=0

∴M≡(2m−c​,2c​)

So, x=2m−c​,y=2c​

∴x21​+y21​=c24m2​+c24​

=c24​(1+m2)

=c24​×p2c2​

∴x21​+y21​=p24​