The perpendicular form of the line 2x + 2
3
y + 11 = 0 is
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2
Answer:
perpendicular form =xcosα+ysinα=P
Putting in standard form,
y=
sinα
−cosαx
+
sinα
P
y=mx+c
m=−cotα
m of given line =
2
3
−2
=
3
−1
cotα=
3
1
α=tan
−1
(
3
)=
3
π
+nπ[n∈integer]
sinα
P
=
2
3
−11
P=
2
3
−11
sin(
3
α
nα)=±
4
11
OptionB
xcos
3
4π
+ysin
3
4π
=
11/4
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