Question

the perpendicular form of the line √3x-y+6 =0 is​

Answer 1

Step-by-step explanation:

Given: Line √3x -y + 5 = 0 and distance of 3 units from the origin. To find: The equation of a line perpendicular to the line √3x -y + 5 = 0 and at a distance of 3 units from the origin. Explanation: The line perpendicular to √3x -y + 5 = 0 is x + √3x + λ = 0 It is given that the line x + √3x + λ = 0 is at a distance of 3 units

x

√1+3=3

Substituting the value of λ, We get x + √3y ± 6 = 0. Hence, equation of the required line is x + √3y ± 6 = 0