Question

The perpendicular from A on side BC of a
triangle ABC intersects BC at D such that DB = 3 CD. Prove that 2AB²=2AC² + BC².​

Answer 1

Answer:

Triangles. The perpendicular from A on side BC of a ∆ABC intersects BC at D such that DB = 3 CD. Prove that 2AB2 = 2AC2 +BC2. Given: A triangle ABC in which AD ⊥ BC and DB = 3CD.

Step-by-step explanation:

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Answer 2

Answer:

see the attachment! Hope it helps uh!

Just the diagram is laterally inverted otherwise everything is same.