Math, asked by helenfaustina12, 2 months ago

The perpendicular from A on side of a ∆ABC intersects BC at ‘D’ such that DB=3CD.Prove that 2AB²=2AC²+BC².

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Answered by sshakuntala1977

4

Answer:

BD = 3CD

BC = BD+CD = 3CD+CD = 4CD

Proving is in the attached photo

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