Math, asked by monishaborah666, 11 months ago

The perpendicular from 'A' on the side BC of a triangleABC intersects BC at D such that BD:CD=3:2 Prove that AB^2-AC^2=1/5BC^2

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Answered by RvChaudharY50
4

Answer:

[ Mark as brainlist if you understand my solution ]

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