Question

The perpendicular from the center of a circle to a chord bisect the chord.​

Answer 1

Answer:-

To prove that the perpendicular from the centre to a chord bisect the chord.

consider a circle with centre at O and AB is a chord such that OX perpendicular to AB to prove that AX =BX <O×A = <O × B [ both are 90]

OA = OB ( both are radius of circle)

OX = OX ( common side )

a OAX =~ a OBX ( a = Angle )

AX = BX ( by property of congruent traingles )

hence proved.

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