Math, asked by sahushrishti49, 19 days ago

The perpendicular from the centre of a circle to a chord bisect the chord
solve the above theorem​

Answers

Answered by harshgrawa543
0

Answer:

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Answered by anirudhsc
2

Answer:

Om = Om (Common)

Ao = Bo (radii)

angle 1 = angle 2 (each 90)

triangle Aom = triangle Bom (SAS)

AM = BM ( by CPCT)

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