Question

the perpendiculars drawn from B and C of a triangle ABC intersect BC and AC at p and q . prove that triangle APC and BQC are similar. Hence show that, PC:BC= QC:AC


please answer the question and DON'T SPAM​

Answer 1

In triangle ABD and ACD

angle B=angle C

AD=AD. (common)

and,

AB = AC (as triangle is isosceles triangle)

hence, by SAS rule

triangle ABD =~ triangle ACD