the person is standing at a distance of 80 m from a church looking at it stop the angle of elevation is of 45 degree find the height of the church
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Ans. 80m
Explanation...
Let a Right ∆ABC in which BC is church and A is position of man.Now...
In ∆ABC...
Tan A = BC/AB
Tan 45° = BC/80
1= BC/80
BC = 80m
Explanation...
Let a Right ∆ABC in which BC is church and A is position of man.Now...
In ∆ABC...
Tan A = BC/AB
Tan 45° = BC/80
1= BC/80
BC = 80m
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pratiksuryawanshi1:
yess thanks but you draw a diagram related to this question and send me the photo
right answer
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